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NEW QUESTION: 1
What security solution is deprecated in the 802.11 standard and should never be used in any modern
WLAN deployment?
A. Shared Key Authentication
B. AES
C. CCMP
D. Open System Authentication
Answer: A
NEW QUESTION: 2
Things to be aware of when the device uses RS485 communication networking (). (Multiple Choice)
A. The distance of the line should not exceed 1000 meters
B. It is recommended to use outdoor shielded twisted pair cable for communication cable.
C. Communication cables should avoid interference sources during wiring
D. When wiring, separate the communication line from the power line
Answer: A,B,C,D
NEW QUESTION: 3
消費者向け電話の導入と企業WLANへのタブレットは、802.11a/b/g/n配備に、影響を及ぼすことができます。 Apple iPhone 4とiPad 2は非常に一般的な例です。
どの声明が、これらの装置の能力を最も記述しますか？
A. Apple iPhone 4はわずか2.4GHzを使います、そして、iPad 2は5GHzを使うだけです。Apple iPhone 4は1本の空間流れだけを使います、iPad 2は2本の空間流れを使います。
B. Apple iPhone 4は2.4GHzを使います、そして、iPad 2は2.4GHzまたは5GHzを使います。Apple iPhone 4は1本の空間流れを使うだけです、iPad 2は2本の空間流れを使います。
C. Apple iPhone 4は2.4GHzを使います、そして、iPad 2は2.4GHzまたは5GHzを使います。Apple iPhone 4とiPad 2は、1つの空間流れだけを使います
D. Apple iPhone 4とiPad 2は、2.4GHzと5GHzを使います。Apple iPhone 4は1本の空間流れだけを使います、iPad 2は2本の空間流れを使います。
Answer: C
NEW QUESTION: 4
View the Exhibit and examine the structure of the EMPLOYEES table. You want to display all employees and their managers having 100 as the MANAGER_ID. You
want the output in two columns: the first column would have the LAST_NAME of the managers
and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.managerjd=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.managerjd=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100;
Answer: B