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NEW QUESTION: 1
組織は、AWS VPCでWebアプリケーションをホストすることを計画しています。法的要件のため、組織はパブリッククラウドでデータベースをホストすることを望んでいません。このシナリオで組織はどのようにセットアップできますか？
A. 組織は、組織のデータセンターのパブリックサブネットとデータベースにアプリサーバーを計画し、それらをVPNゲートウェイに接続する必要があります。
B. 組織は、パブリックサブネット上にアプリサーバーを計画し、パブリックサブネット内にないようにプライベートサブネット内のデータベースを計画する必要があります。
C. 組織は、アプリサーバーにパブリックサブネットを使用し、ストレージゲートウェイでRDSを使用して、ローカルデータセンターからのデータに安全にアクセスし、同期する必要があります。
D. 組織は、パブリックサブネット上でアプリサーバーを計画し、安全なデータ操作のためにプライベートサブネットでRDSを使用する必要があります。
Answer: A
Explanation:
Virtual Private Cloud（VPC）は、ユーザーのAWSアカウント専用の仮想ネットワークです。ユーザーは、VPC内の要件に従ってサブネットを作成できます。ユーザーが自分のデータセンターからVPCに接続する場合、ハードウェアVPNアクセスを使用してデータセンターに接続するパブリックおよびVPNのみのサブネットをセットアップできます。ユーザーがウィザードでこのセットアップを構成すると、VPNサブネットのすべてのトラフィックをルーティングする仮想プライベートゲートウェイが作成されます。仮想プライベートゲートウェイがVPCで接続されている場合、ユーザーがコンソールからVPCを削除すると、まずゲートウェイが自動的に切断され、その後VPCが削除されます。
http://docs.aws.amazon.com/AmazonVPC/latest/UserGuide/VPC_Subnets.html
NEW QUESTION: 2
On a UNIX platform, which three processes are required to be running on all nodes before initiating a cluster database creation? (Choose three.)
A. crsd.bin
B. evmd.bin
C. racgmon.bin
D. ocssd.bin
Answer: A,B,D
NEW QUESTION: 3
What is the limitation of employing Sticky Decision Function?
A. With SDF enabled, only ClusterXL in legacy mode is supported
B. With SDF enabled, the involved VPN Gateways only supports IKEv1
C. With SDF enabled, you can only have three Sync interfaces at most
D. Acceleration technologies, such as SecureXL and CoreXL are disabled when activating SDF
Answer: D
Explanation:
Explanation/Reference:
Reference: https://sc1.checkpoint.com/documents/R76/CP_R76_ClusterXL_AdminGuide/7290.htm
NEW QUESTION: 4
This question will ask you to provide a section of missing code. Given the input SAS data set LABRAW:
Which DO LOOP will create the output SAS data set WORK.LAB_NEW?
A. do i=1 to 2;
visit=i;
date=dat{i};
result=num{i};
end;
output;
B. do i=1 to 2;
do j=1 to 2;
visit=i;
date=dat{j};
result=num{j};
end;
output;
end;
C. do i=1 to 2;
visit=i;
date=dat{i};
result=num{i};
output;
end;
D. do i=1 to 2;
do j=1 to 2;
visit=i;
date=dat{j};
result=num{j};
output;
end;
Answer: C