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NEW QUESTION: 1
HOTSPOT
You have an Azure subscription named Subscription1. Subscription1 contains the resources in the following table:

VNet1 is in RG1. VNet2 is in RG2. There is no connectivity between VNet1 and VNet2. An administrator named Admin1 creates an Azure virtual machine VM1 in RG1. VM1 uses a disk named Disk1 and connects to VNet1. Admin1 then installs a custom application in VM1.
You need to move the custom application to VNet2. The solution must minimize administrative effort.
Which two actions should you perform? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

NEW QUESTION: 2
The Summit5i provides a total of 16 user ports from which 12 are either 100/1000 Ethernet (RJ-45) or 1000 Ethernet (MT-RJ) and the last 4 are unpopulated GBIC-based 1000BASE-X ports.
A. TRUE
B. FALSE
Answer: A

NEW QUESTION: 3
2台のメールボックスサーバーと2台のクライアントアクセスサーバーを含むExchange Server 2013組織があります。
両方のメールボックスサーバーを含むデータベース可用性グループ（DAG）があります。
パブリックフォルダを展開する必要があります。
あなたは最初に何をすべきですか？
A. New-MailboxDatabaseコマンドレットを実行して-PublicFotderDatabaseパラメーターを指定します。
B. New-PublicFolderコマンドレットを実行して-Pathパラメーターを指定します。
C. New-PublicFolderDatabaseコマンドレットを実行して-Serverパラメーターを指定します。
D. New-Mailboxコマンドレットを実行して、-Publicfolderパラメーターを指定します。
Answer: D
Explanation:
説明/参照：
Explanation:
新しい組織にパブリックフォルダを設定する、New-Mailbox -PublicFolder -Name MasterHierarchy。
参考文献：

NEW QUESTION: 4
次の表を含むデータベースがあります。 すべてのテーブルはProductionスキーマにあります。

飲料カテゴリのすべての商品の商品名のリストを返すクエリを作成する必要があります。
以下のガイドラインを使用してクエリを構築します。
* テーブルエイリアスとしてテーブル名の最初の文字を使用してください。
* 2部構成の列名を使用してください。
* オブジェクト名を角括弧で囲まないでください。
* 暗黙的な結合は使用しないでください。
* 変数を使わないでください。
* リテラル値を囲むには一重引用符を使用してください。
正しいTransact-SQLの一部は、以下の回答領域にあります。 問題を解決し、記載されている目標または要件を満たすコードを回答領域に入力します。 提供されているコード内およびその下にコードを追加できます。

あなたの仕事を確かめるためにCheck Syntaxボタンを使ってください。 構文エラーやスペルミスは、行と文字の位置によって報告されます。 構文は必要に応じて何度でも確認できます。
Answer:
Explanation:
Please see explanation
Explanation
1 SELECT p.productname
2 FROM Production.categories AS c
3 inner join production.products as p on c.categoryid=p.categoryid
4 WHERE c.categoryname = 'Beverages'
Note: On line 3 change * to =