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NEW QUESTION: 1
Welches BEST beschreibt den Zweck der Aktivität zur Verbesserung der Wertschöpfungskette?
A. Bereitstellung neuer und verbesserter Dienste und Funktionen zur Verwendung
B. Organisation einer größeren Verbesserungsinitiative in mehrere kleinere Initiativen
C. Kontinuierliche Verbesserung aller Produkte und Dienstleistungen in allen Wertschöpfungskettenaktivitäten
D. Sicherstellung eines gemeinsamen Verständnisses der Vision und der Verbesserungsrichtung für alle Produkte und Dienstleistungen
Answer: C
Explanation:
"The purpose of the improve value chain activity is to ensure continual improvement of products, services, and practices across all value chain activities and the four dimensions of service management."
https://www.symphonysummit.com/products/defining-industry-terms-itsm-itil-itil4/#:~:text=Improve%20%E2%80%93%E2%80%9CThe%20purpose%20of%20the,four%20dimensions%20of%20service%20management.%E2%80%9D
NEW QUESTION: 2
IPプロトコル送信の説明を左側から右側のIPトラフィックタイプにドラッグします。
Answer:
Explanation:
NEW QUESTION: 3
The management at a national consumer goods organization implements a fair work and pay practice as well as a policy to treat employees equitably and consistently. Which common characteristics of fraud will the practice and policy most likely reduce?
A. Commitment.
B. Rationalization.
C. Opportunity.
D. Pressure or incentive.
Answer: D
NEW QUESTION: 4
Consider the following information about a fund. The fund has been in existence for 3 years. Over this period it has achieved a mean monthly return of 3% with a sample standard deviation of monthly returns of 5%. It was expected to earn a 2.5% mean monthly return over the 3-year period.
You want to test a claim that the investment disciplines of the fund result in a standard deviation of monthly returns of less than 6%.
At the 0.05 level of significance:
A. we do not reject the null hypothesis.
B. we are unable to make a decision.
C. we reject the alternative hypothesis.
Answer: A
Explanation:
At the 0.05 level of significance we reject the null hypothesis.
2 2 2 2 2
x = [(n - 1) s ] /o = 35 x 5 /6 = 24.306.
0
2
On the table at 35 degrees of freedom under the 0.95 column, we find the x value. We use 50 since there is no value for 35. At 50 the value is 34.764.
We will fail to reject the null if we find that chi-square is less than 34.764. 24.306 is less than 34.764, so we fail to reject the null hypothesis.