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NEW QUESTION: 1
Examine the structure of the EMPLOYEES table:
Which INSERT statement is valid?
A. INSERT INTO employees(employee_id, first_name, last_name, hire_date) VALUES ( 1000, 'John', 'Smith', 01-Jan-01);
B. INSERT INTO employees(employee_id, first_name, last_name, Hire_date) VALUES ( 1000, 'John', 'Smith', To_date('01/01/01'));
C. INSERT INTO employees (employee_id, first_name, last_name, hire_date) VALUES ( 1000, 'John', 'Smith', '01/01/01');
D. INSERT INTO employees(employee_id, first_name, last_name, hire_date) VALUES ( 1000, 'John', 'Smith', '01 January 01');
Answer: A
Explanation:
Explanation/Reference:
Explanation: It is the only statement that has a valid date; all other will result in an error.
Answer A is incorrect, syntax error, invalid date format
NEW QUESTION: 2
수비 라인 맨은 그의 힘을 키우기 위해 훈련을 합니다. 다음 중 자신의 목표를 최대화하는 휴식 기간은 어느 것입니까?
A. 30 ~ 60 초
B. 5-10 분
C. 60-90 초
D. 2-5 분
Answer: D
NEW QUESTION: 3
What can best be defined as a strongly protected computer that is in a network protected by a firewall (or is part of a firewall) and is the only host (or one of only a few hosts) in the network that can be directly accessed from networks on the other side of the firewall?
A. A screened subnet
B. A bastion host
C. A dual-homed host
D. A proxy server
Answer: B
Explanation:
The Internet Security Glossary (RFC2828) defines a bastion host as a strongly protected computer that is in a network protected by a firewall (or is part of a firewall) and is the only host (or one of only a few hosts) in the network that can be directly accessed from networks on the other side of the firewall. Source: SHIREY, Robert W., RFC2828: Internet Security Glossary, may 2000.
NEW QUESTION: 4
View the Exhibit and examine the structure of CUSTOMERS table.
Using the CUSTOMERS table, you need to generate a report that shows an increase in the credit limit by 15% for all customers. Customers whose credit limit has not been entered should have the message "Not Available" displayed.
Which SQL statement would produce the required result?
A. SELECT NVL (TO CHAR(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
B. SELECT NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
C. SELECT NVL(cust_credit_limit), 'Not Available') "NEW CREDIT"FROM customers;
D. SELECT TO_CHAR (NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
Answer: A