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NEW QUESTION: 1
Refer to the exhibit.
The network is converged. After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?
A. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0
O 208.149.23.96 [110/3] via 190.173.23.10, 00:00:16, FastEthernet 0/0
B. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0
O 208.149.23.96 [110/3] via 190.172.23.10, 00:00:16, Serial 1/0
C. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0
O 208.149.23.96 [110/13] via 190.172.23.10, 00:00:16, Serial 1/0
O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
D. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0
O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
Answer: D
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 /
Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets - B is not correct.
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps =
64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link ->
Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 - C &
D are not correct.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 - they are surely incorrect.
NEW QUESTION: 2
You must deal with performance problems in your storage subsystem. Your application is mainly doing large writes. What can you do to increase performance?
A. Configure in-order delivery to gain structured writes.
B. Switch to drives with a slower response time to get more time for the writes.
C. Verify stripe size and increase it to gain performance.
D. Extend the queue length to keep the array controller busy.
Answer: C
Explanation:
Explanation/Reference: Array Technology - Module 7
The stripe size can have the following impact:
-If it is too large, poor load balancing occurs across the drives.
-If it is too small, excessive cross-stripe transfers (split I/Os) occur. Split I/Os involve two disks; both disks seek, rotate, and transfer data. The response time depends on the slowest disk. Split I/Os reduce the request rate because there are fewer drives to service incoming requests. The optimum stripe size for a given application is shown in the following table.
Type of server application Suggested stripe size change
Mixed read/write Accept the default value Mainly sequential read (such as audio/video applications) Use larger stripe sizes for best performance Mainly write (such as image manipulation applications) Use smaller stripes for RAID 5, RAID 6 Use larger stripes for RAID 0, RAID 1+0
NEW QUESTION: 3
What is the world's smallest business-class desktop that delivers a high level of performance and takes care of everyday computing needs with the 7th Gen Intel processors?
A. HP ProDesk 400 G4MT/SFF
B. HP EliteBook x360 1030 G2
C. HP ProOne 400 AIO G3
D. HP ProDesk 400 G3 DM
Answer: D
Explanation:
Reference: https://www.copaco.com/wp-content/uploads/2017/03/HP-ProDesk-400-Series- G3-G4.pdf
NEW QUESTION: 4
Which OS does the current version of AWS Elastic Beanstalk use?
A. Amazon Linux AMI only
B. Amazon Linux AMI, Windows Server 2003 R2 AMI or the Windows Server 2008 R2 AMI
C. Windows Server 2008 R2 AMI only
D. Amazon Linux AMI or the Windows Server 2008 R2 AMI
Answer: D
Explanation:
The current version of AWS Elastic Beanstalk uses the Amazon Linux AMI or the Windows Server 2008 R2 AMI.
https://aws.amazon.com/elasticbeanstalk/faqs/