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NEW QUESTION: 1
A network administrator connects his PC to the INTERNAL interface on a FortiGate unit. The administrator attempts to make an HTTPS connection to the FortiGate unit on the VLAN1 interface at the IP address of 10.0.1.1, but gets no connectivity.
The following troubleshooting commands are executed from the CLI:
user1 # get system interface == [ internal ] namE. internal modE. static ip: 10.0.1.254 255.255.255.128 status: up netbios-forwarD. disable typE. physical mtu-overridE. disable == [ vlan1 ] namE. vlan1 modE. static ip: 10.0.1.1 255.255.255.128 status: up netb ios-forwarD. disable typE. vlan mtu-overridE. disable
user1 # get router info routing-table all Codes: K - kernel, C - connected, S - static, R - RIP, B - BGP O - OSPF, IA - OSPF inter area N1 - OSPF NSSA external type 1, N2 - OSPF NSSA external type 2
E1 - OSPF external type 1, E2 - OSPF external type 2
i - IS-IS, L1 - IS-IS level-1, L2 - IS-IS level-2, ia - IS-IS inter area
* - candidate default
S 10.0.0.0/8 [10/0] is a summary, Null
C 10.0.1.0/25 is directly connected, vlan1
C 10.0.1.128/25 is directly connected, internal
user1 # diagnose debug flow trace start 100
user1 # diagnose debug ena
user1 # diagnose debug flow filter daddr 10.0.1.1 10.0.1.1
id=20085 trace_id=277 msg="vd-root received a packet(proto=6, 10.0.1.130
:47922->10.0.1.1:443) from internal."
id=20085 trace_id=277 msg="allocate a new session-00000b21"
id=20085 trace_id=277 msg="iprope_in_check() check failed, drop"
Based on the output from these commands, which of the following is a possible cause of the problem?
A. The PC is using an incorrect default gateway IP address.
B. The FortiGate unit has no route back to the PC.
C. There is no firewall policy allowing traffic from INTERNAL -> VLAN1.
D. The PC has an IP address in the wrong subnet.
Answer: C

NEW QUESTION: 2
展示を参照してください。
ネットワークアソシエートは、次のコマンドでOSPFを設定しました。
市（config-router）＃network 192.168.12.64 0.0.0.63 area 0
設定が完了すると、アソシエートはすべてのインターフェイスがOSPFに参加しているわけではないことを検出します。展示物に示されているインターフェイスのうちどれがこの設定ステートメントに従ってOSPFに加わるでしょうか。 （3つ選んでください。）

A. Serial0/0
B. Serial0/1.102
C. Serial0/1.104
D. Serial0/1.103
E. FastEthernet0 /0
F. FastEthernet0 /1
Answer: A,B,F
Explanation:
The "network 192.168.12.64 0.0.0.63 equals to network 192.168.12.64/26. This network has:
Increment: 64 (/26= 1111 1111.1111 1111.1111 1111.1100 0000)Network address:
192.168.12.64
Broadcast address: 192.168.12.127Therefore all interface in the range of this network will join OSPF - B C D are correct.

NEW QUESTION: 3
Instructions
This item contains several questions that you must answer. You can view these questions by clicking on the corresponding button to the left. Changing questions can be accomplished by clicking the numbers to the left question. In order to complete the questions, you will need to refer to the topology.
To gain access to the topology, click on the topology button of the screen. When you have finished viewing the topology, you can return to your questions by clicking on the Questions button to the left.
Each of the windows can be minimized by clicking on the [-]. You can also reposition a window by dragging it by the title bar.
Scenario
Refer to the topology. The diagram represents a small network with a single connection to the Internet.

Users on the 192.168.1.0/24 network must access files located on the Server 1. What route could be configured on router R1 for file requests to reach the server?
A. ip route 192.168.1.0 255.255.255.0 209.165.100.250
B. ip route 0.0.0.0 0.0.0.0 209.265.200.226
C. ip route 209.165.200.0 255.255.255.0 192.168.1.250
D. ip route 0.0.0.0 0.0.0.0 s/0/0/0
Answer: D
Explanation:
Explanation/Reference:
Explanation:
In order to allow the network of 192.168.1.0/24 to access Server 1, we need to establish a default route.
The format of this default route is as follows:
ip route prefix mask {ip-address interface-type interface-number [ip-address]}
[ distance] [name]
[ permanent track number] [tag tag]
Based on the request of this subject, we need to configure the correct route as follows:
ip route 0.0.0.0 0.0.0.0 s0/0/0