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NEW QUESTION: 1
You want to add a field ZZPRICE to the SAP standard transparent table EKKO.
Which of the following actions result in an enhancement of the SAP standard?
There are 2 correct answers to this question.
Response:
A. Add ZZPRICE to the customizing include for the table
B. Insert ZZPRICE into an SAP structure for the table
C. Insert ZZPRICE at the end of the table
D. Create an append structure and add ZZPRICE to it.
Answer: A,D

NEW QUESTION: 2
Which of the following is the preferred method for adding static routes in GAiA?
A. In the CLI with the command "route add"
B. In SmartDashboard under Gateway Properties > Topology
C. Explanation:
QUESTIONNO: 689
Which command will erase all CRL's?
A. vpn crladmin
B. cpstop/cpstart
C. vpn crl_zap
D. vpn flush
D. In Web Portal, under Network Management > IPv4 Static Routes
E. In the CLI via sysconfig
Answer: D

NEW QUESTION: 3
What is the easiest way to enable SD-Access for all your remote site after you have your campus SD-Access fabric up and running?
A. Treat all the sites as one fabric domain and use the traditional physical network as the underlay
B. Use a separate fabric domain for each site and use the traditional physical network as the underlay
C. Use a separate fabric domain for each site and use SD-WAN as the underlay
D. Treat all the sites as one fabric domain and use SD-WAN as the underlay
Answer: D

NEW QUESTION: 4
You are developing an ASP.NET web application.
The application includes the following Entity Data Model (EDM): You instantiate an ObjectContext for the EDM named context.

You need to find the total number of addresses that are associated with customers that have a non-null middle name.
Which LINQ to Entities query should you use?
A. var query = context.Customers .Where(c => c.MiddleName != null) .Select(c => c.CustomerAddresses.Count();
B. var query = context.Addresses .SelectMany(a => a.CustomerAddresses.OfType<Customer>() .Where(c => c.MiddleName != null)).Count();
C. var query = context.Customers .Where(c => c.MiddleName != null) .SelectMany(c => c.CustomerAddresses.Count();
D. var query = context.Addresses .GroupBy(a => a.CustomerAddresses .Where(ca => ca.Customer.MiddleName != null)).Count();
Answer: C