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NEW QUESTION: 1
展示を参照してください。
NOCエンジニアは、SSL VPNトンネルでいくつかの事前ログインパラメーターを調整する必要があります。
表示される情報から、エンジニアはプレログインセッション属性を見つけるためにどこにナビゲートする必要がありますか？
A. "contractor" Connection Profile
B. "engineer1" AAA/Local Users
C. DfltGrpPolicy Group Policy
D. "engineering" Group Policy
Answer: A
Explanation:
Explanation
http://www.cisco.com/en/US/docs/security/vpn_client/anyconnect/anyconnect30/administration/guide/ac05hosts
NEW QUESTION: 2
You are in the process of monitoring the various project processes and their performance. Which of the following are you LEAST concerned with during this process?
A. Reviewing and approving all recommended corrective and preventive actions
B. Providing forecast to update current schedule information
C. Monitoring the implementation of approved changes
D. Comparing actual project performance against project management plan
E. Analyzing and tracking project risks
F. Assessing information to determine whether corrective actions are necessary
Answer: A
NEW QUESTION: 3
You are a program manager for your organization. You have proposed a program to the management that will last four years and will cost $35 million to create. Management has asked to see the program charter and the proposed costs and benefits of the program.
Management agrees to your program charter and proposed to fund the program in increments at the completion of each milestone. What type of funding does management proposed for this program?
A. Milestone approval
B. Step funding
C. Tentative
D. Phase gate estimating
Answer: B
NEW QUESTION: 4
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.0.0.0.0.1
B. 許可10.0.0.0.255.255.255.254
C. 許可10.0.0.1.0.0.0.254
D. 許可10.0.0.1.0.0.0.0
Answer: C
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network .x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.