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NEW QUESTION: 1
OSI (Open System Interconnection) 모델의 어떤 계층이 다른 계층에 의존하며 정보의 구조, 해석 및 처리와 관련이 있습니까?
A. 세션 계층
B. 프레젠테이션 레이어
C. 전송 계층
D. 애플리케이션 계층
Answer: B

NEW QUESTION: 2
コースの前日、講師は教科書の情報が古く、新しい版が利用可能であることを発見します。インストラクターがとるべき最善の行動は次のうちどれですか？
A. コースをそのまま提示しますが、更新された情報を組み込みます。
B. 学習者の利益を最大化するために、更新されたカリキュラムを取得します。
C. コース設計者が設定したとおりにコースを提示します。
D. トレーニングマネージャーに、クラスの前にコースを調整するよう依頼します。
Answer: A

NEW QUESTION: 3
Which additional OSPF states does an OSPF router go through when forming an adjacency with a DR or BDR that it does not go through with a DROTHER? (Select three.)
A. loading state
B. exchange state
C. two-way state
D. init state
E. down state
F. full state
Answer: A,B,F
Explanation:
The correct answers are D, E and F.
Choices a, d, and e are incorrect because an OSPF router will go through these three states with all OSPF routers: DROTHERs, DRs, and BDRs

NEW QUESTION: 4

In the diagram above, ABCD is a square with an area of 100 cm2 and lines BD and AC are the diagonals
of ABCD. If line EF is parallel to line BC and the length of line CF = 32 cm, which of the following is equal
to the shaded area?
A. 25 cm2
B. 64 cm2
C. 78 cm2
D. 89 cm2
E. 39 cm2
Answer: E
Explanation:
Explanation/Reference:
The area of a square is equal toS2where s is the length of one side of the square. A square with an area
of 100cm2has sides that are each equal to100 = 10 cm. The diagonal of a square is equal to2times the
length of a side of the square. Therefore, the lengths of diagonals AC and BD are 102 cm. Diagonals of a
square bisect each other at right angles, so the lengths of segments OB and OC are each52 cm. Since
lines BC and EF are parallel and lines OC and OB are congruent, lines BE and CF are also congruent.
The length of line OF is equal to the length of line OC plus the length of line CF:52 + 32 = 82 cm. In the
same way, OE =OB + BE =52 + 32 = 82 cm. The area of a triangle is equal to1/2bh, where b is the base of
the triangle and h is the height of the triangle. EOF is a right triangle, and its area is equal to The size of
the

shaded area is equal to the area of EOF minus one-fourth of the area of ABCD: