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NEW QUESTION: 1
Which two statements regarding device management on FortiManager are true? (Choose two.)
A. FortiGate devices in an HA cluster that has five VDOMs are counted as five separate devices.
B. The maximum number of managed devices for each ADOM is 500.
C. FortiGate in transparent mode configurations are not counted toward the device count on FortiManager.
D. FortiGate devices in HA cluster devices are counted as a single device.
Answer: A,D
NEW QUESTION: 2
会社は、Dynamics 365 for Finance and Operationsを実装しています。
在庫品目を入力できるようにシステムをセットアップする必要があります。
シナリオに適合する変換単位を選択する必要があります。
どの変換タイプを使用する必要がありますか？回答するには、回答エリアで適切なオプションを選択します。
注：それぞれの正しい選択には1ポイントの価値があります。
Answer:
Explanation:
References:
https://docs.microsoft.com/en-us/dynamicsax-2012/appuser-itpro/set-up-units-and-unit-conversions-retail-essentials
NEW QUESTION: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.1.0.0.0.0
B. Permit 10.0.0.0.255.255.255.254
C. Permit 10.0.0.0.0.0.0.1
D. Permit 10.0.0.1.0.0.0.254
Answer: D
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.