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NEW QUESTION: 1
다음 리소스 그룹이 포함된 Subscription1이라는 Azure 구독이 있습니다.
* 이름 : RG1
* 지역 : 미국 서부
* 태그 : "tag1": "value1"
다음 구성을 사용하여 Policy1이라는 Azure 정책을 Subscription1에 할당합니다.
* 제외 : 없음
* 정책 정의 : 태그 추가 및 기본값
* 과제 명 : Policy1
* 매개 변수 :
-태그 이름 : Tag2
-태그 값 : Value2
Policy1이 할당되면 다음 구성을 가진 저장소 계정을 만듭니다.
* 이름 : storage1
* 위치 : 미국 서부
* 자원 그룹 : RG1
* 태그 : "tag3": "value3"
각 리소스에 할당 된 태그를 식별해야 합니다.
무엇을 식별해야 합니까? 답변하려면 답변 영역에서 적절한 옵션을 선택하십시오.
참고 : 각각의 올바른 선택은 1 포인트의 가치가 있습니다.
Answer:
Explanation:
Explanation
Box 1: "tag1": "value1" only
Box 2: "tag2": "value2" and "tag3": "value3"
Tags applied to the resource group are not inherited by the resources in that resource group.
References:
https://docs.microsoft.com/en-us/azure/azure-resource-manager/resource-group-using-tags
NEW QUESTION: 2
Sie haben einen Arbeitsgruppencomputer mit dem Namen Computer1, auf dem Windows 10 ausgeführt wird. Computer1 verfügt über die in der folgenden Tabelle aufgeführten Benutzerkonten:
Computer1 verfügt über die in der folgenden Tabelle aufgeführten lokalen Gruppenrichtlinien.
Sie erstellen die Richtlinie Lokaler Computer \ Administratoren, die in der folgenden Tabelle aufgeführt ist.
Sie erstellen die Richtlinie Lokaler Computer \ Nicht-Administratoren, die in der folgenden Tabelle aufgeführt ist.
Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
Answer:
Explanation:
Explanation
Reference:
https://docs.microsoft.com/en-us/previous-versions/windows/it-pro/windows-vista/cc766291(v=ws.10)
NEW QUESTION: 3
View the Exhibit and examine the structure of the PROMOTIONS table.
You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?
A. SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date > ALL (SELECT promo_begin_date FROM promotions WHERE promo_category = 'INTERNET');
B. SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date > ALL (SELECT MAX(promo_begin_date) FROM promotions )AND promo_category = 'INTERNET';
C. SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date > ANY (SELECT promo_begin_date FROM promotions WHERE promo_category = 'INTERNET');
D. SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date IN (SELECT promo_begin_date FROM promotions WHERE promo_category='INTERNET');
Answer: A