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NEW QUESTION: 1
What are disadvantages of using Fibre Channel Arbitrated Loop (FC-AL) rather than fabric Channel switched Loop (FC-SW) topology? (Select two.)
A. The bandwidth is shared among all active nodes.
B. The failure of a port is isolated from the other ports.
C. FC-AL topology is usually more expensive than FC-SW.
D. Only one pair of ports can communicate- at the same time.
E. Multiple pairs of ports communicate at the same time.
Answer: A,D
NEW QUESTION: 2
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)
In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:
SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p ______________ sales s
ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?
A. FULL OUTER JOIN
B. RIGHT OUTER JOIN
C. LEFT OUETR JOIN
D. JOIN
Answer: A,C
NEW QUESTION: 3
There have been some failures of the company's internal facing website. A security engineer has found the WAF to be the root cause of the failures. System logs show that the WAF has been unavailable for 14 hours over the past month, in four separate situations. One of these situations was a two hour scheduled maintenance time, aimed at improving the stability of the WAF. Using the MTTR based on the last month's performance figures, which of the following calculations is the percentage of uptime assuming there were 722 hours in the month?
A. 98.34 percent
B. 99.72 percent
C. 98.06 percent
D. 92.24 percent
Answer: C
Explanation:
A web application firewall (WAF) is an appliance, server plugin, or filter that applies a set of rules to an HTTP conversation. Generally, these rules cover common attacks such as cross-site scripting (XSS) and SQL injection. By customizing the rules to your application, many attacks can be identified and blocked.
14h of down time in a period of 772 supposed uptime
= 100 - (14/772 x 100)
= 100 - (1.94)
= 98.06%
References:
Gregg, Michael, and Billy Haines, CASP CompTIA Advanced Security Practitioner Study Guide, John Wiley & Sons, Indianapolis, 2012, pp. 43, 116