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NEW QUESTION: 1
Exhibit:
Referring to the exhibit, which three statements about route 10.222/16 are correct when using the default BGP advertisement rules? (Choose three)
A. R1 will prepend AS10 when advertising 10.222/16 to R2.
B. R1 will advertise 10 222/16 to R2 with itself as the next hop.
C. R7 will advertise 10.222/16 to R9 with itself as the next hop.
D. R2 will advertise 10.222/16 to R4 with itself as the next hop.
E. R2 will prepend AS10 when advertising 10.222/16 to R7.
Answer: B,D,E
NEW QUESTION: 2
Which of the following would represent a violation of the chain of custody when a backup tape has been identified as evidence in a fraud investigation? The tape was:
A. sealed in a signed envelope and locked in a safe under dual control.
B. kept in the tape library' pending further analysis.
C. handed over to authorized independent investigators.
D. removed into the custody of law enforcement investigators.
Answer: B
Explanation:
Since a number of individuals would have access to the tape library, and could have accessed and tampered with the tape, the chain of custody could not be verified. All other choices provide clear indication of who was in custody of the tape at all times.
NEW QUESTION: 3
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
B. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
C. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
D. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
Answer: A
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network 10.10.10.0/24 is 20 + 50 = 70.
Before a router can be considered a feasible successor, it must pass the feasibility condition rule.
In short, the feasibility condition says that if we learn about a prefix from a neighbor, the advertised
distance from that neighbor to the destination must be lower than our feasible distance to that
same destination.
Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the
feasibility condition.