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NEW QUESTION: 1
Which requirement is best implemented using a Wait step in a case
A. You cannot proceed in an expense report until a manager approves the request
B. You need to send an email after a user completes a form
C. You need to pause a case until a user uploads a signed document
D. You cannot complete a purchase case on a website unless you complete a new account subcase
Answer: D

NEW QUESTION: 2
You use the Azure Machine Learning SDK in a notebook to run an experiment using a script file in an experiment folder.
The experiment fails.
You need to troubleshoot the failed experiment.
What are two possible ways to achieve this goal? Each correct answer presents a complete solution.
A. View the log files for the experiment run in the experiment folder.
B. View the logs for the experiment run in Azure Machine Learning studio.
C. Use the get_details_with_logs() method of the run object to display the experiment run logs.
D. Use the get_output() method of the run object to retrieve the experiment run logs.
E. Use the get_metrics() method of the run object to retrieve the experiment run logs.
Answer: B,C
Explanation:
Explanation
Use get_details_with_logs() to fetch the run details and logs created by the run.
You can monitor Azure Machine Learning runs and view their logs with the Azure Machine Learning studio.
Reference:
https://docs.microsoft.com/en-us/python/api/azureml-pipeline-core/azureml.pipeline.core.steprun
https://docs.microsoft.com/en-us/azure/machine-learning/how-to-monitor-view-training-logs

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) csWHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: D