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NEW QUESTION: 1
あなたはABC.comでデータベース管理者として働いています。あなたは展示物を注意深く研究します。
示す

PROMOTIONSテーブルを使用して、2001年1月1日以降に行われたすべてのプロモーションの名前を最新のプロモーションから表示する必要があります。
どのクエリで必要な結果が得られますか？ （該当するものをすべて選択してください。）
A. 。 SELECT promo_name、promo_begin_dateFROMプロモーションWHERE
promo_begin_date> '01 -JAN-01'ORDER BY 1 DESC;
B. 。 SELECT promo_name、promo_begin_dateFROMプロモーションWHERE
promo_begin_date> '01 -JAN-01'ORDER BY 2 DESC;
C. 。 SELECT promo_name、promo_begin_dateFROMプロモーションWHERE
promo_begin_date> '01 -JAN-01'ORDER BY promo_name DESC;
D. SELECT promo_name、promo_begin_date "START DATE" FROM PromotionsWHERE promo_begin_date> '01 -JAN-01'ORDER BY "START DATE" DESC;
Answer: B,D

NEW QUESTION: 2
You need to create an alert that is triggered when the number of seconds that a page stays in the buffer pool without references is less than 1.000.
In the New Alert dialog box. how should you configure the alert? To answer, select the appropriate option from each list in the answer area.

Answer:
Explanation:

Explanation:
References:

NEW QUESTION: 3
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?

A. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via
190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.