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NEW QUESTION: 1
Given the code fragment:

What is the result?

A. Option A
B. Option D
C. Option C
D. Option B
Answer: C

NEW QUESTION: 2
Examine this function:

Execute the query:
SELECT remap_schema FROM dual;
Which is the correct output from the query?
A. CREATE TABLE “EMP” (“EMPNO” NUMBER (4,0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9),
“MGR” NUMBER (4,0), “HIREDATE”
DATE, “SAL” NUMBER (7, 2) , “COMM” NUMBER (7, 2), “DEPTNO” NUMBER (2,0), CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”) USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255
STORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2417483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
BUFFER_POOL DEFAULT FLASH_CHACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
TABLESPACE “SYSAUX” ENABLE,
CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”)
REFERENCES “DEPT” (“DEPTNO”) ENABLE
) SEGMENT CREATION IMMEDIATE
PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255
NOCOMPRESS LOGGING
STORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
TABLESPACE “SYSAUX”
B. CREATE TABLE “EMP” (“EMPNO” NUMBER (4,0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9),
“MGR” NUMBER (4,0), “HIREDATE”
DATE, “SAL” NUMBER (7,2) , “COMM” NUMBER (7,2), “DEPTNO” NUMBER (2,0),
CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)
USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255
STORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2417483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
BUFFER_POOL DEFAULT FLASH_CHACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
TABLESPACE “USERS” ENABLE,
CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”)
REFERENCES “DEPT” (“DEPTNO”) ENABLE
) SEGMENT CREATION IMMEDIATE
PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255
NOCOMPRESS LOGGING
STORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
TABLESPACE “USERS”
C. CREATE TABLE “SCOTT”. “EMP” (“EMPNO” NUMBER (4, 0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9), “MGR” NUMBER (4, 0), “HIREDATE” DATE, “SAL” NUMBER (7, 2), “COMM” NUMBER (7, 2), “DEPTNO” NUMBER (2, 0), CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)
USING INDEX ENABLE,
CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”)
REFERENCES “DEPT” (“DEPTNO”) ENABLE)
D. CREATE TABLE “EMP” (“EMPNO” NUMBER (4, 0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9), “MGR” NUMBER (4, 0), “HIREDATE” DATE, “SAL” NUMBER (7, 2), “COMM” NUMBER (7, 2),
“DEPTNO” NUMBER (2, 0),
CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)
USING INDEX ENABLE,
CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”)
REFERENCES “DEPT” (“DEPTNO”) ENABLE)
Answer: D

NEW QUESTION: 3
Which of the following about Type 10 opaque LSAs is TRUE?
A. Type 10 opaque LSAs are stored in an LSDB.
B. Type 10 opaque LSAs are flooded to all areas of the routing domain.
C. Type 10 opaque LSAs are used for traffic engineering support.
D. Type 10 opaque LSAs are supported by IS-IS.
Answer: C