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NEW QUESTION: 1
Which SQL statement will allow user USER1 to create a view on a table named EMPLOYEE?
A. GRANT CREATETAB ON DATABASE TO user1
B. GRANT REFERENCES ON TABLE employee TO user1
C. GRANT SELECT ON TABLE employee TO user1
D. GRANT CREATEVIEW ON DATABASE TO user1
Answer: C
NEW QUESTION: 2
Refer to the exhibit.
Which route will be advertised by the Cisco ASA to its OSPF neighbors?
A. 10.40.29.0/24
B. 10.40.29.0/24
C. 10.39.23.0/24
D. 10.66.42.215/32
Answer: C
NEW QUESTION: 3
A visitor lands on an Eloqua tracked page for the first time from a search engine, visits the pages on your website, and then leaves. Which type of visitor is this person?
A. Profile
B. Known
C. Linked
D. Unknown
Answer: D
NEW QUESTION: 4
Sie arbeiten für ein Unternehmen, das mobile Anwendungen entwickelt. Sie unterhalten einen Server, auf dem die Spieleraufzeichnungen ihren verschiedenen Spielen zugewiesen werden. Das Trackingsystem ist neu und in Entwicklung.
Die Anwendung verwendet Entity Framework, um eine Verbindung zu einer Azure-Datenbank herzustellen. Die Datenbank enthält eine Spielertabelle und eine Spieltabelle.
Beim Hinzufügen eines Spielers sollte der Code einen neuen Spielerdatensatz einfügen und eine Beziehung zwischen einem vorhandenen Spielerdatensatz und dem neuen Spielerdatensatz hinzufügen.
Die Anwendung ruft CreatePlayerWithGame mit der richtigen gameId und der playerId auf, um den Vorgang zu starten.
(Zeilennummern dienen nur als Referenz.)
Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
Answer:
Explanation:
Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}