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NEW QUESTION: 1
A SysOps Administrator is maintaining an application that runs on Amazon EC2 instances behind an Application Load Balancer (ALB). Users are reporting errors when attempting to launch the application. The Administrator notices an increase in the HTTPCode_ELB_5xx_Count Amazon CloudWatch metric for the load balancer.
What is a possible cause for this increase?
A. The ALB received a request from a client, but the client closed the connection.
B. The ALB target group does not contain healthy EC2 instances.
C. The ALB security group is not configured to allow inbound traffic from the users.
D. The ALB is associated with private subnets within the VPC.
Answer: B
Explanation:
https://docs.aws.amazon.com/elasticloadbalancing/latest/classic/elb-cloudwatch-metrics.html
NEW QUESTION: 2
A. Dsamain
B. Netdom
C. Dsmod
D. Ntdsutil
Answer: D
Explanation:
*To create or delete an application directory partition Open Command Prompt. Type:ntdsutil At the ntdsutil command prompt, type:domain management At the domain management command prompt, type:connection At the server connections command prompt, type:connect to server ServerName At the server connections command prompt, type:quit At the domain management command prompt, do one of the following:
*partition management Manages directory partitions for Active Directory Domain Services (AD DS) or Active Directory Lightweight Directory Services (AD LDS). This is a subcommand of Ntdsutil and Dsmgmt. Ntdsutil and Dsmgmt are command-line
tools that are built into Windows Server 2008 and Windows Server 2008 R2. / partition management create nc %s1 %s2 Creates the application directory partition with distinguished name %s1, on the Active Directory domain controller or AD LDS instance with full DNS name %s2. If you specify "NULL" for %s2, this command uses the currently connected Active Directory domain controller. Use this command only with AD DS. For AD LDS, use create nc %s1 %s2 %s3. Note:
*An application directory partition is a directory partition that is replicated only to specific domain controllers. A domain controller that participates in the replication of a particular application directory partition hosts a replica of that partition.
NEW QUESTION: 3
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
F. CustNo IS NULL
G. CustNo
H. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
I. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
J. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
K. CustNo = L.CustNo
Answer: H
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO
FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx